Look at these two dice.
The first one is a normal dice, the second one is a cheat's dice. Clearly, the cheat's dice is better. In a contest, chances are $5/6$ that the cheat wins, and $1/6$ that there is a draw.
Let's say that dice $A$ is better than dice $B$ when $A$ is expected to win over $B$ in more than half the contests.
Question. Is it possible to find dice $A$, $B$, and $C$ such that $A$ is better than $B$, which is better than $C$, which is better than $A$?